Skip to main content

Implicitly typed local variables


It is not a new feature anymore, but I realized few of my friends still do not know the benefits and need of it. Thus, I feel it is worth writing. This post may not be helpful for you experts!!!
Example to start of with and put few questions
        public void ImplicitVars()
        {
            var i = 0;
            var s = "Do I know";
            Console.WriteLine("i is of type {0}",i.GetType().FullName);
            Console.WriteLine("s is of type {0}",s.GetType().FullName);
        }

Output
i is of type System.Int32
s is of type System.String
Now add another line after second Console.WriteLine - i = "Error";
public void ImplicitVars()
{
var i = 0;
var s = "Do I know";
Console.WriteLine("i is of type {0}",i.GetType().FullName);
Console.WriteLine("s is of type {0}",s.GetType().FullName);
i = "Error";
}
We will get a compile time error. “Cannot implicitly convert type string to int.

This means that
1. Type of a “Implicitly typed local variable” is resolved by the compiler at compilation itself (NOT AT RUNTIME).
2. var DOES NOT mean variant and thus we can not assign different types to same variable.
The question is Why do we need “Implicitly typed local variable” if they are acting just like explicitly typed variables.

Usage
‘var’ is useful when we are working with anonymous types and when we are using LINQ.

Anonymous Types
var v = new { Name = “Anuj”, Age = 26};
Console.WriteLine(“Name : {0}” + Environment.NewLine + “Age : {1}”,v.Name,v.Age);

LINQ

var studentQuery = from student in students where student.Age > 20 select student;

Here “students” is a collection of student type objects. We can very well use foreach on the collection by declaring the variable explicitly but we are using LINQ to write more concise code. So it is up to you to decide what to use, we are really not getting anything extra by using var.

List<student> objStudent = students;
foreach(student s in students)
{
if(s.Age > 20)
{
Do something….
}
}
we have not got any collection so either we need to declare a variable or need to perform action there only (Do something..).

Restrictions
We can not use var while declaring data members at class level. Which is logically correct as with members we define a contract for the object we are going to get and operations we can perform.
Thus we can use only while declaring local variables (inside a function).

Comments

Popular posts from this blog

Laravel XAMPP MySQL artisan migrate install error mysql.sock

In my previous post I wrote about setting up Laravel 4 on Mac with XAMPP . When I tried to use migrations (using artisan) I faced some issue. I will also post about Laravel migrations soon.    php artisan migrate:install Error :                                                     [PDOException]                                       SQLSTATE[HY000] [2002] No such file or directory                                              Solution : We need to tell artisan which mysql we want it to use. For this to work we need to porivde it with mysql.sock which we want it to use. So change your database settings like this: 'mysql' => array( 'driver'    => 'mysql', 'host'      => 'localhost',     'unix_socket' => '/Applications/xampp/xamppfiles/var/mysql/mysql.sock', 'database'  => 'wedding', 'username'  => 'root', 'password'  => '', '

Add (Drop) a new article (table) at publisher in merge replication

Let us add the article using the GUI first. First of all create the table on publisher database. Now right click on the publisher and select properties from the menu. Click on articles. Uncheck the - "Show only checked articles in the list" checkbox, in order to see the newly added table. Select the table as shown in the figure below. Press ok The article has now been added to the publisher We now need to recreate the snapshot Right click the publication and select – “View snapshot agent status”. Click start to regenerate snapshot. Now right click on the subscription (I have both on same server you may have on different servers) and select “View synchronization status” Click on start on the agent. The schema changes will propagate to the client if you have "Replicate schema changes" property set to true in the publisher.

Check SQL Server Job status (State) using sp_help_job and xp_sqlagent_enum_jobs

This article is about checking the status of a SQL job. In our work place we have lot of SQL jobs. These jobs will run whole day and are business critical. They will load the data and generate extracts which will be used by business people. Thus, it becomes quite essential to support the system efficiently so that the job finishes in time and as desired. Also, while designing a new system sometimes we need to check the dependency of one job over another. In such scenario we need to check whether a particular job has finished or not. All this can be achieved in SQL Server by using the procedures:- sp_help_job xp_sqlagent_enum_jobs Note: xp_sqlagent_enum_jobs is an undocumented proc inside of sp_help_job and is used extensively to get SQL agent job information. sp_help_job: This procedure gives some insight into the status, and information, about a job. This stored procedure provides information such as last start time, job status etc. Syntax sp_help_job { [ @job_id= ] jo